For example, if A (3,2) is 1+2i and B A.', then the element B (2,3) is also 1+2i. If A contains complex elements, then A.' does not affect the sign of the imaginary parts. You could also cut out the shiftdim entirely: distances = permute(c,)Īlso, I don't have much experience with Coder, but does it really require all those initializations with zeros? They seem unnecessary. Syntax B A.' B transpose (A) Description example B A.' returns the nonconjugate transpose of A, that is, interchanges the row and column index for each element. The workaround is to use permute, since the transpose is a general case of permute: % after shiftdim:ĭistances = permute(d,) % same as d' for 2d array, but handles 3d However, in your case, you just want to be able to transpose. 1.27K subscribers 180 Share 14K views 3 years ago Quick MATLAB Tutorials In this video I'll go over how we can use the transpose operator in MATLAB to easily switch the rows and columns of a. The issue addressed in the above documentation pertains to the use of the size function.
By contrast, size(A) in MATLAB returns a variable-length output because it drops trailing singleton dimensions.įor example, if the shape of array A is :?x:?x:? and size(A,3)=1, size(A) returns: In generated code, size(A) returns a fixed-length output because it does not drop trailing singleton dimensions of variable-size N-D arrays.
#Matlab transpose matrix code
The docs describe this as an Incompatibility with MATLAB in Determining Size of Variable-Size N-D Arrays ( d is created in a loop, so seems to be variable size):įor variable-size N-D arrays, the size function can return a different result in generated code than in MATLAB. How can I resolve this problem? Furthermore, for my own edification, why is matlab coder unable to correctly assign the dimensions of my variables, specifically a, b, c, d, and distances? However, it fails to correctly shift the dimensions of d, and gives it a size of :? x :? x :?. The d = shiftdim(c,1) line should then yield a 2D matrix of size :? x :?, which I then transpose. Matlab coder identifies c to be of size 1 x :? x :?, which is correct. The problem occurs at the second line below, where it throws an error because it cannot transpose an ND matrix.
Potential_mat(counter,:) = sum(potentials,1) Potentials = repmat(potentials(:,ind_kron(:)'),vec_repmat) Ind_kron = repmat(1:size(potentials,2),) Potential_mat = zeros(num_coord_atoms,num_divs^dof) Ī = coordFile_mat(:,1:len_stat_atoms(i),j) ī = zeros(3,len_stat_atoms(i),num_stat_atoms(i)) Ĭ = zeros(1,len_stat_atoms(i),num_stat_atoms(i)) ĭ = zeros(len_stat_atoms(i),num_stat_atoms(i)) ĭistances = zeros(num_stat_atoms(i),len_stat_atoms(i)) Ind_cr,len_stat_atoms,num_stat_atoms,num_coord_atoms.įunction potential_mat = func_test(i,coordFile_mat,radii_mat,stat_mat. Potential_mat = func_test(i,coordFile_mat,radii_mat,stat_mat. I am trying to use matlab coder to do so. I have a function (with the code given below) that I wish to convert into a MEX file.
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